Riaz Malik Community Member 1 Post
Re: How do I calculate the agitator power in terms of volume increasing?14 December 2013 at 3:31amHaving calculated the agitator power requirements, and following your advice, if the power of agitator is 20 HP, we need to have a motor of 40 HP. Is that correct? Secondly, what if you are using a gear drive - will that be of 40 HP or 20 HP rating? For that, if I am not wrong, the motor has to be of lesser power. I am focusing on power consumption factor too and not over doing anything.
Dave Dickey Forum Moderator 349 Posts
Re: How do I calculate the agitator power in terms of volume increasing?16 December 2013 at 2:09pm
The impeller power required for the Glass-Lined Reactor described in this question is about 5 kW at 3.75 kL. The recommended motor is 7.5 kW. The power requirement for this same reactor at 5 kL does not change, about 5 kW. The volume of fluid in the reactor will have no effect on the amount of power required to rotate the agitator. The mixing intensity will not be as great at 5 kL as it is at 3.75 kL, but the power to the impeller will not change.
The answers by this expert are based on the best available interpretation of the information provided. The consequences of the application of this information are the responsibility of the user. If clarification is needed, please submit a further question.
The power consumption for both volumes is the same, as long as the impeller is fully submerged. The high viscosity will prevent the formation of a significant vortex, even with no baffles. The estimated power consumption is 4.9 kW. The viscosity adjusted power number for these operating conditions is 0.923.
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