How do I calculate the agitator power in terms of volume increasing?
Diameter of reactor-1.95m
Diameter of agitator-1.1m
speed-96rpm
Volume of rector-6.3 kL
Volume of material-3.75 kL
Viscosity of material-30000 cp
density of material-800 kg/m3
reactor type- GLR
Agitor type- 3 blade propeller
no baffles
What is the power consumption of this volume? I am increasing the volume of material up to 5 kL what is the power consumption in the same reactor, same material?
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Re: How do I calculate the agitator power in terms of volume increasing?
26 July 2010 at 1:29pmThe power consumption for both volumes is the same, as long as the impeller is fully submerged. The high viscosity will prevent the formation of a significant vortex, even with no baffles. The estimated power consumption is 4.9 kW. The viscosity adjusted power number for these operating conditions is 0.923.
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