How do I calculate the agitator power in terms of volume increasing? Diameter of reactor-1.95m Diameter of agitator-1.1m speed-96rpm Volume of rector-6.3 kL Volume of material-3.75 kL Viscosity of material-30000 cp density of material-800 kg/m3 reactor type- GLR Agitor type- 3 blade propeller no baffles What is the power consumption of this volume? I am increasing the volume of material up to 5 kL what is the power consumption in the same reactor, same material?
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Dave Dickey Forum Moderator 246 Posts
Re: How do I calculate the agitator power in terms of volume increasing?26 July 2010 at 1:29pmThe power consumption for both volumes is the same, as long as the impeller is fully submerged. The high viscosity will prevent the formation of a significant vortex, even with no baffles. The estimated power consumption is 4.9 kW. The viscosity adjusted power number for these operating conditions is 0.923.